Math, asked by Thaarukeshini, 10 months ago

If sin 3A=cos 2A,3A < 90 degree,the value of A is

Answers

Answered by aftabalam0076892
4

Answer:

sin 3A=cos 2A

cos(90-3A)=cos 2A

90-3A=2A

90 =5A

18=A

Answered by TanikaWaddle
1

The value of A is 18°

Step-by-step explanation:

Given :

sin 3A=cos 2A and 3A < 90°

therefore

converting sinA into cos A

we know that cos (90-A) = sin A

thus ,

sin 3A=cos 2A

cos (90-3A) = cos 2A

cancelling cos from both sides

90-3A = 2A

90 = 2A+ 3A

90= 5A

A = \frac{90}{5}

A = 18°

hence , The value of A is 18°

#Learn more:

Sin 3A × sin³ A+ cos 3A× cos³A= cos³ 2A

https://brainly.in/question/10807173

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