Question

If sin 3A = Cos ( A - 10)° , where 3A is an acute angle , then find the value of A.

Answer 1

Hey !!


★ Here is your answer ★


Sin 3A = Cos ( A - 10 )



=> Cos ( 90 - 3A ) = Cos ( A - 10 )



=> 90 - 3A = A - 10



=> 4A = 100



=> A = 25°


Hence,


A = 25°

Answer 2

Given sin 3A=cos(A − 10)
⇒ cos(90 − 3A) = cos(A − 10)
⇒ (90 − 3A) = (A − 10)
⇒ 4A = 100
∴ A = 25 degree