If sin 3A = COS (A-18), where
3A is an acute angie, Find the valueOfA
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Given⏩
sin3A = cos( A - 18)
We know ⏩
sin A = cos (90° - A)
So,
sin3A = cos( A - 18)
=> cos ( 90° - 3A ) = cos ( A - 18)
Therefore,
90° -3A = A - 18°
=> 4A = 90°-18°
=> A = 72°/4
=> A = 18°
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