Question

If sin 3A=cos (A-2°) where 3A and (A-2°) are both acute angle then A=?

Answer 1

Heya mate, Here is ur answer

We know that Sin Theta = Cos (90-theta)

So,

Sin 3A = Cos (A-2)

Cos (90-3A) =Cos (A-2)

90-3A=A-2

90+2=A+3A

92=4A

92/4=A

23=A

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@Laughterqueen

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Answer 2

sin3A=cos(A-2)
cos(90-3A)=cos(A-2)
90-3A=A-2
4A=92
A=92/4
A=23