if sin 3A =cos(A-26 degree) where 3a is an acute angles'find the value of A
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sin3A=cos (A-26)
cos (90-3A)=cos (A-26)
90-3A=A-26
116=4A
A=116/4=29 degree
cos (90-3A)=cos (A-26)
90-3A=A-26
116=4A
A=116/4=29 degree
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