Question

if sin 3A = cos(A=26)
find the value of A​

Answer 1

Answer:

Given us,

3a is an acute angle

sin3a = cos(a - 26)

=> cos(90-3a)= cos(a -26)

=> 90 - 3a = a - 26

=> -3a - a = - 26-90

=> -4a = -116

=> a = -116/-4

=> a = 29

hence, a= 29

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Answer 2

Answer:

Sin 3A = Cos ( A - 26 )

Cos ( 90 - 3A ) Cos (A - 26 )

Step-by-step explanation:

90 - 3A = A -26

- 3A - A = -26 - 90

-4A = - 116

A = -116 / -4

A = 29 ....

..

hope it helps you..