Question

if sin 3A = cos (A-26°) ,where 3A is an acute angle ,find the value of A​

Answer 1

Step-by-step explanation:

sin 3A = cos (A-26°)

sin 3A=sin (90-A-26)

3A=64°-A

3A+A=64.

4A=64

A=64/4=16.

A=16°.

Answer 2

Step-by-step explanation:

sin 3A=cos (A-26)

cos(90-3A)=cos (A-26)

90-3A=A-26

90+26=A+3A

116=4A

116/4=A

29=A