Question

If sin 3A=cos (A-26°) where 3A is an acute angle Then find the value of A. ​

Answer 1

Answer:

Nothing understandable

Answer 2

Answer:

sin3A=cos(A-26°)

cos(90-3A)=sin3A

so,

cos(90-3A)=cos(A-26°)

cos cos will be cutted.

Now we get,

90-3A=A-26°

90+26=A+3A

116=3A

A=116/3

A=36°