Question

If sin 3A = cos (A-26°), where 3A is an acute angles , find the value of A . ​

Answer 1

Answer:

sin=cos(A-26°) where 3a is an acute

$angle6514$

Answer 2

Given:-

•  sin 3A = cos(a − 26)
• 3A is an acute angle.

To Find:-

• the value of A.

step-by-step solution:-

⇒ cos(90 − 3a) = cos(a− 26)

⇒ (90 − 3a) = (a − 26)

⇒ 4a = 116°

a = 29°