If sin 3A=cos(A=26o)where 3A is an acute angle find the value of A?
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We know that sin@ =cos(90-@)
cos(90-3A)=cos(A-26)
on comparing
90-3A=A-26
4A=116
A=29
cos(90-3A)=cos(A-26)
on comparing
90-3A=A-26
4A=116
A=29
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