Math, asked by alikatsurrr, 3 months ago

if Sin 3A =Cos (A-6°), find the value of A​

Answers

Answered by yadavraman11912
1

Answer:

sin3A=cos(A-6)

sin(90-3A)=Sin (A-6)

90-3A=A-6

A=24

Step-by-step explanation:

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Answered by Anonymous
1

Answer :

  • Value of A is 24

Given :

  • Sin 3A = cos (A - 6⁰)

To find :

  • Value of A

Solution :

Given ,

  • Sin 3A = cos (A - 6)

⟿ Sin 3A = cos (A - 6)

⟿ Sin 3A = sin(90 - (A - 6)

⟿ Sin(90 - A) = cos A

Then,

⟿ 3A = 90 (A - 6)

⟿ 3A = 90 - A + 6

⟿ 3A + A = 96

⟿ 4A = 96

⟿ A = 96/4

⟿ A = 24

Hence Value of A is 24

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