If Sin 3B = Cos (B – 6) where 3B and (B – 6) are both acute angles, then the value of B is
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1
Answer:
Find the values of
(i) 7 sin 300 cos 600
(ii) 3 sin2 450 + 2 cos2 600
(iii) cos2 450 + sin2 600 + sin2 300
(iv) cos 900 + cos2 450 sin 300 tan 450.
Solution:
(i) 7 sin 300 cos 600
Substituting the values
= 7 × ½ × ½
Step-by-step explanation:
Answered by
1
Answer:
Solution:
(i) 7 sin 300 cos 600
Substituting the values
= 7 × ½ × ½
Step-by-step explanation:
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