Question

if sin 3B=cos (B-6) where 3B and (B-6) are both acute angles, then the value of B is?​

Answer 1

Answer:

we know sin(90-theta) =cosA

Step-by-step explanation:

here;sin3B=cos(B-6)

using identities

sin(90-3B)=cos(B-6)

90-3B=B-6

4B=96

:B=24 answer