Question

If sin 3theta = cos ( theta - 2°), where 3theta and (theta - 2°) are both acute angles, then find theta

Answer 1

sin 3a= cos(a-2) ......1


we know cos( 90-a) =sin. a
so,
cos (90 -3a) = sin 3a
putting this in 1



cos(90-3a) = cos (a - 2)
90-3a=a-2
-3a-a=-2-90
-4a = -92
a = 23

Answer 2

Answer: we can write sin 3theta = cos (90 degree - 3theta)

Hence, cos( 90 degree - 3theta) = cos ( theta - 2 degree)

Equalising both side-

90 degree - 3 theta = theta - 2 degree

90 degree + 2 degree = theta + 3 theta

92 degree = 4 theta

92 degree / 4 = theta

theta = 23 degree.

Hope it'll help you......

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