If sin 3thita = Cos (thita-2), where 3thita and (thita-2) are both acute angles, then find the value of 0.
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Answer: theta = 23°
Step-by-step explanation:
given, sin 3theta = cos (theta - 2)
cos (90 - 3theta) = cos (theta - 2)
90 - 3theta = theta - 2
90 + 2 = theta + 3theta
92 = 4theta
Therefore, theta = 92/4 = 23°
Hope it helped!
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