Question

if sin 3x=1 evaluate cos2x


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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Sin3x=cos2x

3sinx−4sin3x=1−2sin2x

4sin3x−2sin2x−3sinx+1=0

By inspection, we see that sinx=1 is solution of the equation.

We use synthetic division to decompose this equation

1 | 4 -2 -3 1

x 4 2 -1

Step-by-step explanation:

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