Question

if sin(3x+2y) -1, cos (2x -3y) =√3/2

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Answer 1

Answer:

3x+2y =180

2x-3y = 30

multiply both to get 6x

6x+4y=360

6x-9y=90

subtract both the equations we get

15y = 450

y= 30

thus x= 40

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