if sin θ=4/5 find the value of sinθ tanθ-1/ 2tan²θ
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Step-by-step explanation:
sin 0 * sin0 / cos0 -1 / 2 tan^20
sin^ 2 0 -1 / cos0 / 2 tan ^ 2 0
-cos ^ 2 0 / cos 0 / 2 tan ^2 0
cos 0 / tan ^2 0
- cos^ 2 0 * cos 0/ 2 sin^ 2 0
- cos^ 2 0 /2 sin ^2 0
sin^2 0 -1/ 2 sin ^2 0
(4/5)^ 2 - 1/ 2* (4/5)^2
16/25-1/ 32/25
= - 9/32
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