Question

If sin θ = -4/5, what are two possible values for θ between 0° and 360°?​

Answer 1

Answer:

Okay..we know that 3/5 and 4/5 are the values of sin37°and sin53°..

We also know that sine value is negative in third and fourth quadrant

So angle must be 180+53 and 360-53

233 and 307..

We r using 180 and 360 because sin(180+angle)= -sin(angle)

And same with 360..