Question

If Sin 43 = m , find the value of Tan 47??

Answer 1

sin 43° = m
=> sin (90-47°) = m
=> cos 47° = m
$\sin 47 = \sqrt{1 - {cos}^{2}47 } \\ sin47 = \sqrt{1 - {m}^{2} } \\ \tan47 = \frac{sin47 }{cos47} = \frac{m}{ \sqrt{1 - {m}^{2} } }$

Answer 2

Answer:

Tan 47 =$\frac{\sqrt{1-m^2}}{m}$

Step-by-step explanation:

Given :sin 43° = m

To Find : Tan 47

Solution :

sin 43° = m

sin (90-47) = m

$sin(90-\theta)=cos \theta$

Cos 47 = m

We know that $Sin^2\theta =1- Cos^2\theta$

$Sin^2 47 =1- Cos^2 47$

$Sin 47 =\sqrt{1- m^2}$

Tan 47 = $\frac{sin 47}{Cos 47}=\frac{\sqrt{1-m^2}}{m}$

Hence Tan 47 =$\frac{\sqrt{1-m^2}}{m}$