Question

if sin∅ =5/13 then find
a) cos∅ (b) tan∅ (c) cosec ∅ (d) tan ∅ + 1/cos∅​

Answer 1

Answer:

sin theta=p/h = 5/13

b2=h2-p2

=169-25

=144

=12

(a)cos theta=12/13

(b)tan theta=5/12

(c)cosec theta=13/5

(d)tan theta +1/cos theta= 5/12+13/12=18/12