Question

If Sin θ = 5

3 the value of (1 − Cos2 θ) is

A. 9/5
B. 6/10

C. 9/25
D. 25/9​

Answer 1

Given :  Sin θ = 3/5

To Find :   value of  1 - Cos²θ    or  1 - Cos2θ

A)9/5 B)6/10 C)9/25 D)25/9

Solution:

Sin² θ   +  Cos²θ = 1

=> Sin² θ  = 1 -  Cos²θ

Sin θ = 3/5

=> (3/5)² =  1 -  Cos²θ

=> 9/25 = 1 -  Cos²θ

Hence value of  1 -  Cos²θ   is 9/25

1 - Cos2θ

Cos2θ = Cos²θ  - Sin² θ

= 1 - ( Cos²θ  - Sin² θ)

= (  1 -  Cos²θ ) + Sin² θ

=  2 Sin² θ

=  2 ( 9/25)

= 18/25

but 18/25 is not in options

Hence correct Question is  value of  1 - Cos²θ   = 9/25

Learn More

Ifsin 990° sin 780° sin 390°+=K(tan 405° – tan 360°) then Kicos 540 ...

brainly.in/question/22239477

Maximum value of sin(cos(tanx)) is(1) sint (2)

brainly.in/question/11761816

evaluate cot[90-theta].sin[90-theta] / sin theta+cot 40/tan 50 - [cos ...

brainly.in/question/2769339