If Sin 5θ= 4cosθ then θ=?
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If sinθ=4cosθ, then what is the value of sinθcosθ?
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Suppose theta =x.
sinx = 4.cosx. , dividing both sides by cosx.
tanx=4…………………(1)
Now , sinx.cosx =?
= (sinx.cosx)/(1). , putting 1 = cos^2 x + sin^2 x.
= ( sinx.cosx)/(cos^2 x+ sin^2 x). , dividing in Nr and Dr by cos^2 x.
= tanx/(1+tan^2 x). , putting tanx= 4.
= 4/(1+4^2).
= 4/17. Answer.
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