Question

If sin θ = 6/10 , Find the value of sin2 θ + cos2 θ.​

Answer 1

Answer:

sin²θ + cos²θ = 1

Step-by-step explanation:

sin θ = 6/10

sin²θ + cos²θ

= sin²θ + (1-sin²θ)

= (6/10) + [1-(6/10)]

=(6/10) + [ (10-6)/10]

=(6/10) + [ 4/10]

=(6+4)/10

=10/10

=1