Question

If sinθ=6/7 and θ is an acute angle find the other five trigonometric function values of θ?

Answer 1

Answer:

cosq=1-sin^2q

=1-(6/7)^2

=1-(36/49)

=49-36/49

=√13/7

tanq = sinq/cosq

hence ,

(6/7)÷(√13/7)

(6/7)(7)√13)

6/√13

cotq = 1/tanq

hence,

cotq = √13/6

cosecq= 1/sinq

hence,

cosecq = 7/6

secq = 1/cosq

hence,

secq = 7/√13

Answer 2

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