Question

If sin^ = 7/25, find the value of cos^ and tan^​

Answer 1

there is a mistake in your question,

check your question,

where is the angle ? sin^(?)

?=

Answer 2

If sinA = 7/25 , find the value of cos A and tan A

since sinA =7/25

so, according to Pythagoras therom,

AC^2=AB^2+BC^2

So, since sinA = BC/AC

Therefore ,

AB^2= AC^2-BC^2

AB^2= 25^2 - 7^2

AB^2= 625 - 49

AB^2= 576

AB=root over 576

Therefore AB = 24

We got AC = 25 , AB = 24, BC=7

Cos A = AB/AC = 24/25

TAN A = BC/AB = 7/24