If sin(70°‐2A)=cos(3A+10°)then evaluate cos 3A×cos60°‐sin 3A×sin 60°/3+3 tan²3A
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Answer:
sin3A=cos(A−10
o
)⇒cos(90
o
−3A)=cos(A−10
o
)
⇒90
o
+10
o
=3A+A⇒100
o
=4A⇒A=25
Therefore, Answer is 25degree
hope it will help
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