Math, asked by greeshma8751, 8 days ago

If sin(70°‐2A)=cos(3A+10°)then evaluate cos 3A×cos60°‐sin 3A×sin 60°/3+3 tan²3A​

Answers

Answered by bishalnaskar2007
0

Answer:

sin3A=cos(A−10

o

)⇒cos(90

o

−3A)=cos(A−10

o

)

⇒90

o

+10

o

=3A+A⇒100

o

=4A⇒A=25

Therefore, Answer is 25degree

hope it will help

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