Question

if sin =9/b find SecA+tanA in term of a&b​

Answer 1

Answer:

answer is b+9/b-9

Explanation:

sin = 9/b =p/h

so, b^2 = a^2 +81

and, a= b-9

By putting the value of secA + tanA we get,

= b/b-9 + 9/b-9

= b+9/b-9