Question

if sin A = 1/2 and cot B= 1. prove that sin (A+B ) = 1 . A,B 《 90° ??​

Answer 1

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Angle are acute

SinA=1/√2

=sin45°

A=45°

CotB=1

=cot45°

B=45°

Sin(A+B)=sin(45°+45°)

=sin90°

=1

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Answer 2

Angle are acute

SinA=1/√2

=sin45°

A=45°

CotB=1

=cot45°

B=45°

Sin(A+B)=sin(45°+45°)

=sin90°

=1