Question

If sin A = 1/√2 and cot B = 1, prove that sin (A + B) = 1, where A and B both are acute angles.​

Answer 1

Answer:

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Answer 2

✰ Qᴜēsᴛíõñ :-

If sin A = 1/√2 and cot B = 1, prove that sin (A + B) = 1, where A and B both are acute angles.

✪ Söʟúᴛîøɴ :-

sin A = 1/√2 = sin 45° ➙ A = 45°

cot B = 1 = cot 45° ➙ B = 45°

L.H.S sin (A + B) = sin(45° + 45°)

= sin 90°

= 1 = R.H.S

⛬ L.H.S = R.H.S