Question

if sin A=1/✓2 the magnitude of L a is​

Answer 1

Step-by-step explanation:

$we \: know \: \sin(45) = \sin(135) \\ = \sin(2n\pi + 45) (where \: \\ n = \: any \: natural \: number) \\ = \frac{1}{ \sqrt{2} } \: \\ and \: given \sin(a) = \frac{1}{ \sqrt{2} } \\ so \: a \: = 45 \: or \: 135 \: or \: 2n\pi + 45 \\ 45 = \frac{\pi}{4} \\ and \: 135 = \frac{3\pi}{4} \\ and \: 2n\pi + 45 = 2n\pi + \frac{\pi}{4} \\ 2n\pi + 45 = \frac{8n\pi + \pi}{4} \\ 2n\pi + 45 = \frac{\pi(8n + 1)}{4}$

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