Question

IF SIN A= 1/2 THEN FIND THE VALUE OF TAN A

Answer 1

Answer:

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Answer 2

Answer:

The value of  $tanA = \frac{1}{\sqrt{3} }$

Explanation:

$sinA = \frac{P}{H} \\=\frac{1}{2} \\tanA = \frac{P}{B}$

Using pythagoras theorem,

$H^{2} =P^{2} +B^{2} \\2^{2} =1^{2} +B^{2} \\B^{2} = 3\\B = \sqrt{3}$

From the question, we have

$tanA = \frac{P}{B} \\=\frac{1}{\sqrt{3} }$

Addition:

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