Question

if sin A=1/2 then show that 3 cos A minus 4 cos A=0​

Answer 1

Step-by-step explanation:

hence proved

here is your answer

Answer 2

sinA=1/2

Squaring both sides,

sin square A=1/4

now.sin square A +cos square A = 1

or,1/4 + cos square A=1

or,cos square A=1-1/4

or,cos square A=3/4

or,cos A=√3/2

LHS

3cosA-4cosA

3×√3/2-4×√3/2

3√3/2-4√3/2

-√3/2

=0

therefore LHS=R.H.S

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