Question

if sin A=1/3 , evaluate cos A. Cosec A + tan A .sec A

Answer 1

sinA=1/3......then,,


cosecA=3


cosA=1/√8......

secA=√8



now,,,cos A. Cosec A + tan A .sec A =


1/√8×3+√8/3×√8

3/√8+8/3

Answer 2

sinA = perpendicular/hypotenuse = 1/3
=> p = k, h = 3k, => b² = h² - p² = 9k² - k² = 8k² => b = 2√2k
cosA = Base/Hypotenuse = 2√2/3
cosecA = 3
tanA = SinA/CosA = 1/2√2
secA = 3/2√2
= 2√2/3 × 3 + 1/2√2 × 3/2√2
= 2√2 + 3/8 = 16√2 + 3 /8