Question

If sin A=1/3, evaluate cosA cosec A+ tan A sec A

Answer 1

Answer:

(3 +8√8) / 8

Step-by-step explanation:

N = cosA cosec A+ tan A sec A = cosA /sin A+ tan A /cosA

N =  1 /tan A+ tan A /cosA = (tan²A + cosA)÷sinA = 3(1/8+√8/3)

N = (3 +8√8) / 8