Question

if sin A =1/3 , find value of 2 cot square A+ 2 .

Answer 1

Sin = perpendicuar/hypotenuse.
So, Sin A = 1/3
=> P = 1 and H = 3
Cot A = B/P
        = 2root2/1    [B found by pythagoras theorem]
=>2Cot^2A + 2 = 2*8 + 2 = 18 [answer]
refer to the image attached for clear information.
Here P= Perpendicular
B= Base
H= Hypotenuse.