if sin A =1/3 , find value of 2 cot square A+ 2 .
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Sin = perpendicuar/hypotenuse.
So, Sin A = 1/3
=> P = 1 and H = 3
Cot A = B/P
= 2root2/1 [B found by pythagoras theorem]
=>2Cot^2A + 2 = 2*8 + 2 = 18 [answer]
refer to the image attached for clear information.
Here P= Perpendicular
B= Base
H= Hypotenuse.
So, Sin A = 1/3
=> P = 1 and H = 3
Cot A = B/P
= 2root2/1 [B found by pythagoras theorem]
=>2Cot^2A + 2 = 2*8 + 2 = 18 [answer]
refer to the image attached for clear information.
Here P= Perpendicular
B= Base
H= Hypotenuse.
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Reeshabh:
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