if Sin A = 1/3 , find value of Cos A and Tan B .
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Answer:
plize klick on brainlests plize
Step-by-step explanation:
sinA=
3
1
⇒cosA=
1−sin
2
A
=
1−
9
1
=
9
8
=
3
2
2
tanA=
cosA
sinA
=
3
2
2
3
1
=
2
2
1
secA=
cosA
1
=
2
2
3
cosecA=
sinA
1
=3
cosA.cosecA+tanA.secA
=
3
2
2
.3+
2
2
1
.
2
2
3
=2
2
+
8
3
=
8
3+16
2
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