Question

if sin a= 1/3 , than find cos a​

Answer 1

Answer:

cosA= $2\sqrt{2}/3$

Step-by-step explanation:

Side AB=

$\sqrt{3^2-1^2}\\\sqrt{8} \\=2\sqrt{2}\\cosA= 2\sqrt{2}/3$

Answer 2

Answer:

sin A = 1313 Now we will construct a triangle ABC in which ∠B = 90° and BC : AC = 1 : 3 Let BC = k and AC = 3k where k > 0 which is a constant quantity.