Question

If sin A=1/3
then find the value of 9cotA + 9.​

Answer 1

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Answer 2

Answer:

9(√8+1)

Step-by-step explanation:

if sin A =1/3

sin A=p/h

p=1, h= 3

b^2=h^2-p^2 (by Pythagoras theorem)

(3)^2 -(1)^2

(9) -(1)

8

b=√8

then, cot A=b/p

=√8/1

=√8

as per question

9cotA+9

9×(√8)+9

9√8+9

9(√8+1) (taking 9 as common)

•hence solved.

further you solved root (√) Or leave as usual.