Question

If sin A=1/3
then the value of (9 cot^2 A+9) is
(A) 1
(B) 81
(C) 9
(D) 1/81​

Answer 1

Answer: 9

Step-by-step explanation:

sinA = 1/3

sin²A = 1/9

1/cosec²A = 1/9

cosec²A = 9

1 + cot²A = 9 [ cosec²A - cot²A = 1 ]

cot²A = 8

9cot²A= 72

9 cot²A + 9 = 81

9(cot²A + 1) = 81