Question

if sin A=1/3then find the value of cosA, coseA+tanAand secA.​

Answer 1

Answer:

6√2+1/2√2

Step-by-step explanation:

sinA=1/3

p=1

h=3

b=2√2

CosA= b/h= 2√2/3

SecA= h/b= 3/2√2

CosecA = 3

tanA = 1/2√2

=3+1/2√2= 6√2+1/2√2

Hope you understand.

Mark as brainliest.