Question

if sin a = 1/4 then cosA and tan A​

Answer 1

Answer:

sin a = 1/4

p = 1, h= 4

using phyagoran Therom

h²= b²+p²

4²= b²+1²

16-1 = b²

b²= 15

$b= \sqrt{15}$

$cosa = \frac{ \sqrt{15} }{4}$

$tana = \frac{1}{ \sqrt{15} }$

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