Math, asked by pragatibhatt2922, 6 months ago

if sin A =1/root 5, cos B = 3/root 10 where A and B are positive acute angles , prove that A+B=45.

Answers

Answered by pariharamisha55
8

Step-by-step explanation:

sinA=1√5,cosA=√1-sin^2A

cosA=2/√5,tanA=sinA/cosA=1/√5/2/√5

tanA=1/2

cosB=3/√10,sinB=1/√10

tanB=1/3

tan(A+B) =tanA+tanB/1-tanA×tanB

tan(A+B) =1/2+1/3÷1-1/2×1/3

tan(A+B) =3+2/6÷1-1/6

tan(A+B) =5/6÷6-1/6

tan(A+B) =5/6÷5/6

tan(A+B)=1

tan(A+B)=tan45°

(A+B)=1

Answered by abhishek00001
4

Step-by-step explanation:

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