If sin A =1/root10
sin B=1/root5
0<A, B < pie/4 then a+b=
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Answer:
sin(a+b)= sinacosb+ cosasinb
Sina =1/root10
cosa= 3/root10(from pythogreas rule)
sinb= 1/root5
cosb= 2/root5
sin(a+b)= sinpi/4
sin(a+b)= 1/root2
now sin(a+b)= 1/root10 * 2/root5 + 3/root10 * 1/root5
= 2/5root2 + 3/5 root2
= 5/ 5root2
= 1/root2
sin(a+b) = sinpi/4 = 1/root2
therefore a+b = pi/4 is proved
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