Question

if sin A = 1/root2 find the value of cot A

Answer 1

heya friends !!!

it's too easy ...

sinA=p/h. where p is perpendicular b is base and h is height of right angle triangle

◆ (by using Pythagoras theorm )

b=√h^2-p^2

=)b=√(√2)^2-1^2

=)b,=√2-1

b,=√1=1

so, cot ¢=p/b=1/1=1

so :cot¢=cot45°

and ¢=45°.

hope it help you.


@rajukumar ☺

Answer 2

sin A = 1/√2
sin A  = sin 45
A = 45

cot A = 
cot 45 =1