Question

. If sin A = 12/13, calculate the value of cotangent of angle A.​

Answer 1

Answer:

CONCEPT OF TRIGONOMETRIC RATIOS AMD FOUR FUNDAMENTAL OPERATIONS.

Step-by-step explanation:

SO , sin A = 12 / 13 = perpendicular / hypotenuse.

So , Perpendicular = 12 , Hypotenuse = 13 , base = ?

So ,

$(hypotenuse)^{2} = (perpendicular) ^{2} + (base)^{2}$

(PYTHAGORAS THEOREM)

HYPOTENUSE = 13 , PERPENDICULAR = 12 , BASE = ?

BY SUBSTITUTING THE VALUES IN FORMULA ,

${(13)}^{2} = (12)^{2} + (base)^{2}$

${(13)}^{2} - {(12)}^{2} = {(base)}^{2}$

$(13 + 12)(13 - 12) \: = \: {(base)}^{2}$

[BY IDENTITY (a+b)(a-b) = a^2 - b^2]

$(25)(1) \: = \: {(base)}^{2}$

$25 \: = \: {(base)}^{2}$

TAKING ROOT ON BOTH THE SIDES ,

WE GET ,

5 = BASE

SO , cot A = Base / perpendicular

cot A = 5 / 13 [BY SUBSTITUTION METHOD]

[ANSWER] :- THE VALUE OF cot A IS 5 / 13.

HOPE THIS ANSWER HELPS YOU !!!!!!

PLEASE MARK ME AS BRAINLIEST !!!!

AND PLEASE FOLLOW ME !!!!!!!!!!

Answer 2

Answer:

add me fast

Step-by-step explanation:

fast fast fast fast fast