Question

If sin A =12\13 find cos A and Tan A

Answer 1

sinA=p/h=12/13

therefore,p=12andh=13

b²=h²-p2

b²=(13)²-(12)²

b²=169-144

b²=25

b=√25

b=5

hence,cosA=b/h=5/13 and

tan=p/b=12/5