If sin A = 12/13 Find Sec A
Answers
Answered by
6
Answer:
13/5
Step-by-step explanation:
sinA = 12/13
square on both sides:
⇒ sin²A = (12/13)²
⇒ 1 - cos²A = (144/169)
⇒ 1 - (144/169) = cos²A
⇒ (169 - 144)/169 = cos²A
⇒ 5/13 = cosA ⇒ 13/5 = 1/cosA
Hence,
secA = 1/cosA
= 13/5
Answered by
34
Answer:
- 13/5
Step-by-step explanation:
Given
- sin A = 12/13
To find
- Sec A
Solution
1 - cos²A = sin A² :
- cos²A = 1 - (144 / 169)
- cos²A = (169 - 144) / 169
- cos²A = 5 / 13
sec A = 1 / cos A
- 1 / (5 / 3)
- 13/5
∴ sec A = 13/5
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