Math, asked by rockstarregan9799, 1 month ago

If sin A = 12/13 Find Sec A

Answers

Answered by abhi569
6

Answer:

13/5

Step-by-step explanation:

sinA = 12/13

square on both sides:

⇒ sin²A = (12/13)²

⇒ 1 - cos²A = (144/169)

⇒ 1 - (144/169) = cos²A

⇒ (169 - 144)/169 = cos²A

⇒ 5/13 = cosA    ⇒ 13/5 = 1/cosA

  Hence,

secA = 1/cosA

         = 13/5

Answered by CopyThat
34

Answer:

  • 13/5

Step-by-step explanation:

Given

  • sin A = 12/13

To find

  • Sec A

Solution

1 - cos²A = sin A² :

  • cos²A = 1 - (144 / 169)
  • cos²A =  (169 - 144) / 169
  • cos²A = 5 / 13

sec A = 1 / cos A

  • 1 / (5 / 3)
  • 13/5

∴ sec A = 13/5

Similar questions