Question

if sin A=12/3, what is the value of cos A
​

Answer 1

Answer:

sinA = 12/3

we know that,

sin =perpendicular/hypotenuse

Now,

by using pythagores theorem,

H^2 = P^2 + B^2

12^2 = 3^2+ B^2

144= 9+ B^2

$\sqrt{144 - 9} = b {}^{2} \\ \sqrt{135 = b}$

b =

$b = \sqrt{135}$

so,

cosA = b/h

=

$\sqrt{135 } \div 12$