Question

if sin A-18 = cos 2A , find the value of A

Answer 1

Hi buddy

Here is your answer..........

sin(A-18°) = cos2Asin(A-18°) =sin(90°-2A)By comparingA-18 = 90°-2AA +2A =90° +18°3A =108 °A =108/3A = 36{A=36° _________________________________Hope it helps☘ #sibi ❤️

Answer 2

Answer:

sin A-18=sin (90-2A)...(by applying identity ,cos theta =sin 90- theta)....

A-18=90-2A

3A=108

A=36

Step-by-step explanation:

hope it will help you ✌️✌️